wefcdr

In physics, the reduced mass is the "effective" inertial mass appearing in the two-body problem of Newtonian mechanics. It is a quantity which allows the two-body problem to be solved as if it were a one-body problem. Note, however, that the mass determining the gravitational force is not reduced. In the computation one mass can be replaced with the reduced mass, if this is compensated by replacing the other mass with the sum of both masses. The reduced mass is frequently denoted by $mu$ (mu), although the standard gravitational parameter is also denoted by $mu$ (as are a number of other physical quantities). It has the dimensions of mass, and SI unit kg.

Equation

Given two bodies, one with mass m₁ and the other with mass m₂, the equivalent one-body problem, with the position of one body with respect to the other as the unknown, is that of a single body of mass^[1]^[2]

mu =cfrac 1cfrac 1m_1+cfrac 1m_2=cfrac m_1m_2m_1+m_2,!,

where the force on this mass is given by the force between the two bodies.

Properties

The reduced mass is always less than or equal to the mass of each body:

mu leq m_1,quad mu leq m_2!,

and has the reciprocal additive property:

frac 1mu =frac 1m_1+frac 1m_2,!

which by re-arrangement is equivalent to half of the harmonic mean.

In the special case that $m_1=m_2$ :

mu =frac m_12=frac m_22,!

If $displaystyle m_1gg m_2$ , then $displaystyle mu approx m_2$ .

Derivation

The equation can be derived as follows.

Newtonian mechanics

Using Newton's second law, the force exerted by body 2 on body 1 is

mathbf F_12=m_1mathbf a_1.!,

The force exerted by body 1 on body 2 is

mathbf F_21=m_2mathbf a_2.!,

According to Newton's third law, the force that body 2 exerts on body 1 is equal and opposite to the force that body 1 exerts on body 2:

mathbf F_12=-mathbf F_21.!,

Therefore,

m_1mathbf a_1=-m_2mathbf a_2.!,

and

mathbf a_2=-m_1 over m_2mathbf a_1.!,

The relative acceleration a_rel between the two bodies is given by

displaystyle mathbf a_rm rel=mathbf a_1-mathbf a_2=left(1+frac m_1m_2right)mathbf a_1=frac m_2+m_1m_1m_2m_1mathbf a_1=frac mathbf F_12mu .

So we conclude that body 1 moves with respect to the position of body 2 as a body of mass equal to the reduced mass.

Lagrangian mechanics

Alternatively, a Lagrangian description of the two-body problem gives a Lagrangian of

L=1 over 2m_1mathbf dot r _1^2+1 over 2m_2mathbf dot r _2^2-V(|mathbf r _1-mathbf r _2|)!,

where $mathbf r _i$ is the position vector of mass $m_i$ (of particle $i$ ). The potential energy V is a function as it is only dependent on the absolute distance between the particles. If we define

mathbf r =mathbf r _1-mathbf r _2

and let the centre of mass coincide with our origin in this reference frame, i.e.

m_1mathbf r _1+m_2mathbf r _2=0

,

then

displaystyle mathbf r _1=frac m_2mathbf r m_1+m_2,;mathbf r _2=-frac m_1mathbf r m_1+m_2.

Then substituting above gives a new Lagrangian

L=1 over 2mu mathbf dot r ^2-V(r),

where

mu =frac m_1m_2m_1+m_2

is the reduced mass. Thus we have reduced the two-body problem to that of one body.

Applications

Reduced mass can be used in a multitude of two-body problems, where classical mechanics is applicable.

Moment of inertia of two point masses in a line

In a system with two point masses m₁ and m₂ such that they are co-linear, the center of mass may be found via

$displaystyle x_cm=frac m_1x_1+m_2x_2m_1+m_2$ .

The moment of inertia of this system in the center of mass frame of reference is a two-body problem with two masses, each with its own distance to the center of mass. By converting to the equivalent reduced mass frame of reference, the system may be treated as a single reduced mass, μ, with a distance, d, equal to the sum of x₁ and x₂. This is because the rotational axis of the reduced mass frame of reference is through the combined mass, M (the sum of m₁ and m₂)

$displaystyle M=m_1+m_2$

$displaystyle d=x_1+x_2$

$displaystyle mu =frac m_1m_2m_1+m_2=frac m_1m_2M$

The combined mass M is eliminated in the determination of the moment of inertia of the system since it is a point particle (making M the same size as μ, but with greater mass. Images not drawn to scale) along the axis of rotation (via the parallel axis theorem, it's contribution of MR² would be zero since R=0 because M and μ are also point masses). Determining the moment of inertia of the reduced mass (μ) system is equivalent to determining the moment of inertia of the center of mass system.

$displaystyle displaystyle I=frac m_1m_2m_1!+!m_2d^2=mu d^2$

Collisions of particles

In a collision with a coefficient of restitution e, the change in kinetic energy can be written as

Delta K=frac 12mu v_rm rel^2(e^2-1)

,

where v_rel is the relative velocity of the bodies before collision.

For typical applications in nuclear physics, where one particle's mass is much larger than the other the reduced mass can be approximated as the smaller mass of the system. The limit of the reduced mass formula as one mass goes to infinity is the smaller mass, thus this approximation is used to ease calculations, especially when the larger particle's exact mass is not known.

Motion of two massive bodies under their gravitational attraction

In the case of the gravitational potential energy

V(|mathbf r _1-mathbf r _2|)=-frac Gm_1m_2,,

we find that the position of the first body with respect to the second is governed by the same differential equation as the position of a body with the reduced mass orbiting a body with a mass equal to the sum of the two masses, because

m_1m_2=(m_1+m_2)mu !,

Non-relativistic quantum mechanics

Consider the electron (mass m_e) and proton (mass m_p) in the hydrogen atom.^[3] They orbit each other about a common centre of mass, a two body problem. To analyze the motion of the electron, a one-body problem, the reduced mass replaces the electron mass

m_erightarrow frac m_em_pm_e+m_p

and the proton mass becomes the sum of the two masses

m_prightarrow m_e+m_p

This idea is used to set up the Schrödinger equation for the hydrogen atom.

Other uses

"Reduced mass" may also refer more generally to an algebraic term of the form^{[citation needed]}

x^*=1 over 1 over x_1+1 over x_2=x_1x_2 over x_1+x_2!,

that simplifies an equation of the form

1 over x^*=sum _i=1^n1 over x_i=1 over x_1+1 over x_2+cdots +1 over x_n.!,

The reduced mass is typically used as a relationship between two system elements in parallel, such as resistors; whether these be in the electrical, thermal, hydraulic, or mechanical domains. This relationship is determined by the physical properties of the elements as well as the continuity equation linking them.

References

^ Encyclopaedia of Physics (2nd Edition), R.G. Lerner, G.L. Trigg, VHC publishers, 1991, (Verlagsgesellschaft) 3-527-26954-1, (VHC Inc.) 0-89573-752-3

^ Dynamics and Relativity, J.R. Forshaw, A.G. Smith, Wiley, 2009, ISBN 978-0-470-01460-8

^ Molecular Quantum Mechanics Parts I and II: An Introduction to Quantum Chemistry (Volume 1), P.W. Atkins, Oxford University Press, 1977, ISBN 0-19-855129-0

External links

Reduced Mass on HyperPhysics

[1] Encyclopaedia of Physics (2nd Edition), R.G. Lerner, G.L. Trigg, VHC publishers, 1991, (Verlagsgesellschaft) 3-527-26954-1, (VHC Inc.) 0-89573-752-3

[2] Dynamics and Relativity, J.R. Forshaw, A.G. Smith, Wiley, 2009, ISBN 978-0-470-01460-8

[3] Molecular Quantum Mechanics Parts I and II: An Introduction to Quantum Chemistry (Volume 1), P.W. Atkins, Oxford University Press, 1977, ISBN 0-19-855129-0

搜尋此網誌

wefcdr

Reduced mass

Contents