PHP - AJAX and MySQL
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PHP - AJAX and MySQL
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AJAX can be used for interactive communication with a database.
AJAX Database Example
The following example will demonstrate how a web page can fetch information from a database with AJAX:
Example
Example Explained - The MySQL Database
The database table we use in the example above looks like this:
| id | FirstName | LastName | Age | Hometown | Job |
|---|---|---|---|---|---|
| 1 | Peter | Griffin | 41 | Quahog | Brewery |
| 2 | Lois | Griffin | 40 | Newport | Piano Teacher |
| 3 | Joseph | Swanson | 39 | Quahog | Police Officer |
| 4 | Glenn | Quagmire | 41 | Quahog | Pilot |
Example Explained
In the example above, when a user selects a person in the dropdown list
above, a function called "showUser()" is executed.
The function is triggered by the onchange event.
Here is the HTML code:
Example
<html>
<head>
<script>
function showUser(str)
if (str == "")
document.getElementById("txtHint").innerHTML = "";
return;
else
if (window.XMLHttpRequest)
// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp = new XMLHttpRequest();
else
// code for IE6, IE5
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
xmlhttp.onreadystatechange = function()
if (this.readyState == 4 && this.status == 200)
document.getElementById("txtHint").innerHTML = this.responseText;
;
xmlhttp.open("GET","getuser.php?q="+str,true);
xmlhttp.send();
</script>
</head>
<body>
<form>
<select name="users" onchange="showUser(this.value)">
<option value="">Select a person:</option>
<option value="1">Peter Griffin</option>
<option value="2">Lois Griffin</option>
<option value="3">Joseph Swanson</option>
<option value="4">Glenn Quagmire</option>
</select>
</form>
<br>
<div id="txtHint"><b>Person info will be listed here...</b></div>
</body>
</html>Run example »
Code explanation:
First, check if person is selected. If no person is selected (str == ""), clear the
content of txtHint and exit the function. If a person is selected, do the following:
- Create an XMLHttpRequest object
- Create the function to be executed when the server response is ready
- Send the request off to a file on the server
- Notice that a parameter (q) is added to the URL (with the content of the dropdown list)
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The PHP File
The page on the server called by the JavaScript above is a PHP file called "getuser.php".
The source code in "getuser.php" runs a query against a MySQL database, and returns the result in an HTML
table:
<!DOCTYPE html>
<html>
<head>
<style>
table
width: 100%;
border-collapse: collapse;
table, td, th
border: 1px solid black;
padding: 5px;
th text-align: left;
</style>
</head>
<body>
<?php
$q = intval($_GET['q']);
$con = mysqli_connect('localhost','peter','abc123','my_db');
if (!$con)
die('Could not connect: ' . mysqli_error($con));
mysqli_select_db($con,"ajax_demo");
$sql="SELECT * FROM user WHERE id = '".$q."'";
$result = mysqli_query($con,$sql);
echo "<table>
<tr>
<th>Firstname</th>
<th>Lastname</th>
<th>Age</th>
<th>Hometown</th>
<th>Job</th>
</tr>";
while($row = mysqli_fetch_array($result))
echo "<tr>";
echo "<td>" . $row['FirstName'] . "</td>";
echo "<td>" . $row['LastName'] . "</td>";
echo "<td>" . $row['Age'] . "</td>";
echo "<td>" . $row['Hometown'] . "</td>";
echo "<td>" . $row['Job'] . "</td>";
echo "</tr>";
echo "</table>";
mysqli_close($con);
?>
</body>
</html>Explanation: When the query is sent from the JavaScript to the PHP file, the following happens:
- PHP opens a connection to a MySQL server
- The correct person is found
- An HTML table is created, filled with data, and sent back to the "txtHint" placeholder
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